(2y^2-5)(2y^2+5)=

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Solution for (2y^2-5)(2y^2+5)= equation:


Simplifying
(2y2 + -5)(2y2 + 5) = 0

Reorder the terms:
(-5 + 2y2)(2y2 + 5) = 0

Reorder the terms:
(-5 + 2y2)(5 + 2y2) = 0

Multiply (-5 + 2y2) * (5 + 2y2)
(-5(5 + 2y2) + 2y2 * (5 + 2y2)) = 0
((5 * -5 + 2y2 * -5) + 2y2 * (5 + 2y2)) = 0
((-25 + -10y2) + 2y2 * (5 + 2y2)) = 0
(-25 + -10y2 + (5 * 2y2 + 2y2 * 2y2)) = 0
(-25 + -10y2 + (10y2 + 4y4)) = 0

Combine like terms: -10y2 + 10y2 = 0
(-25 + 0 + 4y4) = 0
(-25 + 4y4) = 0

Solving
-25 + 4y4 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 4y4 = 0 + 25

Combine like terms: -25 + 25 = 0
0 + 4y4 = 0 + 25
4y4 = 0 + 25

Combine like terms: 0 + 25 = 25
4y4 = 25

Divide each side by '4'.
y4 = 6.25

Simplifying
y4 = 6.25

Reorder the terms:
-6.25 + y4 = 6.25 + -6.25

Combine like terms: 6.25 + -6.25 = 0.00
-6.25 + y4 = 0.00

Factor a difference between two squares.
(2.5 + y2)(-2.5 + y2) = 0.00

Subproblem 1

Set the factor '(2.5 + y2)' equal to zero and attempt to solve: Simplifying 2.5 + y2 = 0 Solving 2.5 + y2 = 0 Move all terms containing y to the left, all other terms to the right. Add '-2.5' to each side of the equation. 2.5 + -2.5 + y2 = 0 + -2.5 Combine like terms: 2.5 + -2.5 = 0.0 0.0 + y2 = 0 + -2.5 y2 = 0 + -2.5 Combine like terms: 0 + -2.5 = -2.5 y2 = -2.5 Simplifying y2 = -2.5 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(-2.5 + y2)' equal to zero and attempt to solve: Simplifying -2.5 + y2 = 0 Solving -2.5 + y2 = 0 Move all terms containing y to the left, all other terms to the right. Add '2.5' to each side of the equation. -2.5 + 2.5 + y2 = 0 + 2.5 Combine like terms: -2.5 + 2.5 = 0.0 0.0 + y2 = 0 + 2.5 y2 = 0 + 2.5 Combine like terms: 0 + 2.5 = 2.5 y2 = 2.5 Simplifying y2 = 2.5 Take the square root of each side: y = {-1.58113883, 1.58113883}

Solution

y = {-1.58113883, 1.58113883}

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